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ISL5216
Sample filter #2 requires:
? 32 + 32 + 128 + 8 = 200 data RAM locations
SAMPLE FILTER #3 PROGRAM
? (95+1)/2 = 48 coefficient RAM location (resampler and
HBF coefficients are in ROM).
The number of clock cycles required to compute an output
for Sample filter #2 is calculated as follows:
SAMPLE FILTER #2 CLOCK CYCLES CALCULATION
CLOCK
STEP
0
1
INSTRUCTION
Wait for enough input samples (2 in this case)
FIR
Type = even symmetry
19 taps
Halfband
Decimate by 2
Compute one output
CYCLES
20
FUNCTION PERFORMED
Halfband 1 compute clocks
(5 per compute x 4 computes)
Memory block size 32
Memory block start at 0
Coefficient block start at 18
Output to step 2
Reset wait count
8
14
4
48
2
6
Halfband 1 input sample writes (8 input samples)
Halfband 2 compute clocks
(7 per compute x 2 computes)
Halfband 2 input sample writes (4 input samples)
95 tap symmetric FIR, 2 clocks per tap
FIR input sample writes (2 input samples)
Resampler (6 taps, nonsymmetric)
2
3
FIR
Type = even symmetry
30 taps
Decimate by 1
Compute one output
Memory block size 64
Memory block start at 32
Coefficient block start at 64
Step size 1
Output to AGC
Jump, Unconditional, to 0
1
1
1
Resampler input sample write (1 input samples)
Jump instruction
Wait instruction
The number of clock cycles required to compute an output
for Sample filter #3 is calculated as follows:
SAMPLE FILTER #3 CLOCK CYCLES CALCULATION
CLOCK
105
Clock cycles per output
CYCLES
6
FUNCTION PERFORMED
19 tap halfband, one output
Total decimation is 8, so the input sample rate for the FIR
chain (CIC output rate) could be up to:
f CLK /(ceil(105/8)) = f CLK /14.
With a 65MHz clock, this would support a maximum input
sample rate to the FIR processor of 4.6MHz and an output
sample rate up to 0.580MHz. The shaping filter impulse
response length would be:
(95 x 2)/580,000 = 82 μ s.
2
15
1
1
1
26
halfband input writes (2 input samples)
30 tap symmetric FIR, 2 taps per clock
1 FIR input write
1 wait
1 jump
Clock cycles per output
The maximum output sample rate is dependent on the
length and number of FIRs and their decimation factors.
Illustrating this concept with Filter Example #3, a higher
speed filter chain might be comprised of one 19 tap
decimate-by-2 halfband filter followed by a 30 tap shaping
FIR filter with no decimation. The program for this example
could be:
16
For Filter Example #3 and a 65MSPS input, the maximum
FIR input rate would be 65MSPS/ceil(26/2) = 5MSPS giving
a decimate-by-2 output sample rate of 2.5MSPS. At
80MSPS, the FIR could have up to 42 taps with the same
output rate.
Channels 0, 1, 2 and 3 can be combined in a polyphase
structure for increased bandwidth or improved filtering.
Filter Example #4 will be used to demonstrate this capability.
Symbol rate of 4.096 MSym. The desired output sample rate
is 8.192MSPS. Arrange the four back end sections as four
filters operating on the same CIC output at a rate of
FN6013.3
July 13, 2007
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